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## What is the angular velocity of second hand and minute hand of clock?

Since the minute hand of a clock completes a circular revolution in 60 minutes, the angular velocity of the minute hand is, **ω=2π60×60=π1800=1.75×10-3rad⋅s-1** . Since the hour of a clock completes a circular revolution in 12 hours, the angular velocity of the hour hand is, ω=2π12×60×60=π21600=1.45×10-4rad⋅s-1.

## What is angular velocity of Earth?

3. Based on the sidereal day, Earth’s true angular velocity, ωEarth, is equal to 15.04108°/mean solar hour (360°/23 hours 56 minutes 4 seconds). ωEarth can also be expressed in radians/second (rad/s) using the relationship **ωEarth = 2*π /T**, where T is Earth’s sidereal period (23 hours 56 minutes 4 seconds).

## What is angular displacement of minute hand in 20 minutes?

It is simple: In 60 minutes, the minute hands makes a full revolution of 360 degrees. So in 20 minutes it revolves one third, or **120 degrees**.

## Which angular velocity is greater a second hand minute hand and hour hand of a clock?

Solution : The hour hand of a watch takes 12h to complate one rotation i.e. T1=12 hour. And the earth takes 24 hours to rotate once around its axis, i.e. T2=24 hour. i.e., angular speed of hour hand is greater **than the angular speed of earth around its axis**.

## How often does the tip of an hour hand on a clock have the same velocity?

Answer: tip of an hour hand on a clock have the same velocity? **once every minute**; once every hour; once every 12 hours; once every 24 hours.

## What is the angular velocity per hour?

With orbital radius 42,000 km from the earth’s center, the satellite’s speed through space is thus v = 42,000 km × 0.26/h ≈ 11,000 km/h.

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Angular velocity | |
---|---|

Common symbols | ω |

In SI base units | s^{−}^{1} |

Extensive? | yes |

Intensive? | yes (for rigid body only) |

## What is Earth’s Omega?

The rotation rate of the Earth (**Ω = 7.2921 × 10 ^{−}^{5} rad/s**) can be calculated as 2π / T radians per second, where T is the rotation period of the Earth which is one sidereal day (23 h 56 min 4.1 s). In the midlatitudes, the typical value for. is about 10

^{−}

^{4}rad/s.