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## What is period of a clock?

The clock period or cycle time, T_{c}, is **the time between rising edges of a repetitive clock signal**. Its reciprocal, f_{c} = 1/T_{c}, is the clock frequency. … Frequency is measured in units of Hertz (Hz), or cycles per second: 1 megahertz (MHz) = 10^{6} Hz, and 1 gigahertz (GHz) = 10^{9} Hz.

## What is the period of the second hand on an analog clock?

For second hand, period = **1 min = 360 s**; frequency = 0.0166 HzFor minute hand, period = 1 hr = 600 s; frequency = 2.77×10−4HzFor hour hand, period = 12 hrs =3200 s; frequency = 2.3×10−5Hz.

## How is the minimum clock period calculated?

The minimum clock period is **1.5+3+1.5+0.5=6.5 ns**. 2. There are no hold time violations because the minimum flip flop propagation delay is larger than the hold time plus the skew. The maximum delay for the next state logic is 5 ns.

## How many times will be minute hand rotates in one hour?

In one hour, the minute hand makes one revolution and the second hand goes round 60 times. This means that, in one hour, the second hand passes over the minute hand 60 – 1 = **59 times** and the two are also in line (but with 180 degrees between them) 59 times.

## Who invented the clock face?

In the early 11th century, **Ibn al-Haytham’**s Maqala fi al-Binkam described a mechanical water clock that, for the first time in history, accurately measures time in hours and minutes. To represent the hours and minutes, Ibn al-Haytham invented a clock face.

## What is the clock period of a clock frequency of 1 GHz?

Clock Time

It is the reciprocal of the clock frequency. For example, a 1 GHz processor has a cycle time of **1.0 ns** and a 4 GHz processor has a cycle time of 0.25 ns. Clock time is affected by circuit technology and the complexity of the work done in a single clock.

## What is min period violation?

Min pulse width check is **to ensure that pulse width of clock signal is more than required value**. Basically it is based on frequency of operation and Technology. Means if frequency of design is 1Ghz than typical value of each high and low pulse width will be equal to (1ns/2) 0.5ns if duty cycle is 50%.